实现页面跳转

1、重写MainAbilitySlice.java 的onStart()函数

打开第一个页面的“MainAbilitySlice.java”文件，重写onStart()方法添加按钮的响应逻辑，实现点击按钮跳转到下一页，示例代码如下：

package com.example.myapplication.slice;
 
import com.example.myapplication.ResourceTable;
import ohos.aafwk.ability.AbilitySlice;
import ohos.aafwk.content.Intent;
import ohos.aafwk.content.Operation;
import ohos.agp.components.*;
 
public class MainAbilitySlice extends AbilitySlice {
 
    @Override
    public void onStart(Intent intent) {
        super.onStart(intent);
        super.setUIContent(ResourceTable.Layout_main_layout);
        Button button = (Button) findComponentById(ResourceTable.Id_button);
 
        if (button != null) {
            // 为按钮设置点击回调
            button.setClickedListener(new Component.ClickedListener() {
                @Override
                public void onClick(Component component) {
                Intent secondIntent = new Intent();
                // 指定待启动FA的bundleName和abilityName
                Operation operation = new Intent.OperationBuilder()
                        .withDeviceId("")
                        .withBundleName("com.example.myapplication")
                        .withAbilityName("com.example.myapplication.SecondAbility")
                        .build();
                secondIntent.setOperation(operation);
                startAbility(secondIntent); // 通过AbilitySlice的startAbility接口实现启动另一个页面
                }
            });
        }
    }
 
    @Override
    public void onActive() {
        super.onActive();
    }
 
    @Override
    public void onForeground(Intent intent) {
        super.onForeground(intent);
    }
}

注意事项，请将com.example.myapplication替换成您的项目名称

        .withBundleName("com.example.myapplication")
                        .withAbilityName("com.example.myapplication.SecondAbility")

2、再次运行项目，效果如图所示

作者：知识大胖

来源：CSDN